Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:47Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 3 7 ; 2 4 | = -2

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

11t² + 9t + 5 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 4 8 ; 3 5 | = -4

459K

7r² + 8r + 5 = 0

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

PV = nRT

80K

8ψ² + 7ψ + 0 = 0

359K