Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:28Z

3n² + 7n + 7 = 0

12θ² + 2θ + 6 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-ω²) dω = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{10}{6} \sum_{i=1}^{n} i^{2}

2n² + 4n + 0 = 0

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2H₂ + O₂ → 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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det| 5 6 ; 2 6 | = 18

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N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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