Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 02:17Z
\frac{4}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∂y/∂t = 6y
\frac{12}{1} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
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∫₀^∞ e^(-t²) dt = √π / 2
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2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
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