Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

E = mc²

460K

det| 9 4 ; 1 10 | = 86

438K

∫₀^∞ e^(-x²) dx = √π / 2

10ψ² + 5ψ + 0 = 0

186K

det| 3 7 ; 2 4 | = -2

411K

4φ² + 6φ + 2 = 0

e^{i\pi} + 1 = 0

448K

e^{i\pi} + 1 = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

d/dt [t^3] = 3t^2

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