Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z

det| 5 4 ; 6 6 | = 6

∇ × E = −∂B/∂t

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

∇²φ = 0

8ψ² + 7ψ + 0 = 0

186K

∫₀^∞ e^(-x²) dx = √π / 2

411K

det| 12 5 ; 4 13 | = 136

∂n/∂θ = 3n

448K

d/dt [t^3] = 3t^2

22K

∑_{k=1}^{n} k = n(n+1)/2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

459K

E = mc²

406K

CaCO₃ → CaO + CO₂

N₂ + 3H₂ ⇌ 2NH₃

181K

E = mc²

ω = 2πf

CH₄ + 2O₂ → CO₂ + 2H₂O

det| 8 2 ; 1 9 | = 70