Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:28Z

CH₄ + 2O₂ → CO₂ + 2H₂O

6ω² + 4ω + 4 = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 1 1 ; 4 2 | = -2

det| 9 4 ; 1 10 | = 86

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

CaCO₃ → CaO + CO₂

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

448K

iħ ∂ψ/∂t = Ĥψ

22K

det| 8 4 ; 2 9 | = 64

6t² + 6t + 4 = 0

459K

F = G m₁m₂ / r²

406K

4n² + 8n + 6 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

181K

e^{i\pi} + 1 = 0

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2