Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

11t² + 9t + 7 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

E = mc²

411K

4φ² + 6φ + 2 = 0

F = ma

448K

det| 7 2 ; 7 8 | = 42

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

d/dt [t^3] = 3t^2

406K

∇²ω = 0

\lim_{β\to 0} \frac{\sin β}{β} = 1

181K

CH₄ + 2O₂ → CO₂ + 2H₂O

80K

d/dr [r^2] = 2r^1

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

359K

det| 9 4 ; 1 10 | = 86

455K