Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:24Z

F = ma

d/dt [t^3] = 3t^2

273K

ω = 2πf

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

∇ × E = −∂B/∂t

139K

∂β/∂β = 6β

108K

N₂ + 3H₂ ⇌ 2NH₃

∂y/∂n = 5y

333K

8ψ² + 7ψ + 0 = 0

160K

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

439K

det| 10 2 ; 3 11 | = 104

413K

1r² + 8r + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

128K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

404K