Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:54Z

11n² + 5n + 4 = 0

det| 10 7 ; 3 11 | = 89

460K

det| 9 4 ; 1 10 | = 86

438K

∫₀^∞ e^(-x²) dx = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

F = G m₁m₂ / r²

406K

det| 5 2 ; 3 6 | = 24

181K

8θ² + 8θ + 6 = 0

80K