Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:26Z

det| 6 5 ; 4 7 | = 22

∑_{k=1}^{n} k = n(n+1)/2

460K

det| 5 2 ; 3 6 | = 24

438K

∇²φ = 0

det| 7 8 ; 4 8 | = 24

186K

det| 4 8 ; 3 5 | = -4

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

448K

∇²r = 0

22K

F = ma

det| 9 4 ; 1 10 | = 86

459K

d/dt [t^3] = 3t^2

406K

ΔS ≥ 0

∇²t = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K