Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:35Z

∇²t = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

∫₀^∞ e^(-z²) dz = √π / 2

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det| 6 4 ; 3 7 | = 30

det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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ΔS ≥ 0

e^{i\pi} + 1 = 0

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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1z² + 3z + 2 = 0

7y² + 9y + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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7r² + 8r + 5 = 0

80K

11t² + 9t + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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