Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:19Z

∇²n = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

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N₂ + 3H₂ ⇌ 2NH₃

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9r² + 4r + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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11t² + 9t + 5 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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11γ² + 3γ + 6 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

439K

∑_{k=1}^{n} k = n(n+1)/2

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10ψ² + 5ψ + 0 = 0

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E = mc²

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