Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z
10y² + 2y + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 9 ; 1 8 | = 47
459K
λ = h/p
iħ ∂ψ/∂t = Ĥψ
d/dγ [γ^3] = 3γ^2