Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-r²) dr = √π / 2

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

ΔS ≥ 0

448K

10t² + 9t + 5 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

det| 3 7 ; 2 4 | = -2

406K

∇²ω = 0

F = G m₁m₂ / r²

181K

∇ × E = −∂B/∂t

80K

10ω² + 7ω + 4 = 0

359K

det| 7 4 ; 4 8 | = 40

455K