Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:32Z

d/dy [y^8] = 8y^7

∇²β = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

264K

\lim_{x\to 0} \frac{\sin x}{x} = 1

F = G m₁m₂ / r²

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iħ ∂ψ/∂t = Ĥψ

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d/dn [n^3] = 3n^2

∑_{k=1}^{n} k = n(n+1)/2

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iħ ∂ψ/∂t = Ĥψ

411K

6t² + 4t + 0 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

377K

det| 5 2 ; 3 6 | = 24

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det| 9 4 ; 1 10 | = 86

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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F = G m₁m₂ / r²

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