Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²n = 0

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

∇²β = 0

448K

det| 5 9 ; 7 6 | = -33

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

459K

∇ × E = −∂B/∂t

406K

∇²ω = 0

6r² + 3r + 1 = 0

181K

d/dt [t^3] = 3t^2

80K

d/dr [r^2] = 2r^1

7r² + 8r + 5 = 0

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120