Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:37Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

451K

e^{i\pi} + 1 = 0

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det| 8 9 ; 3 9 | = 45

det| 9 4 ; 1 10 | = 86

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det| 1 4 ; 3 2 | = -10

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∑_{k=1}^{n} k = n(n+1)/2

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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det| 2 3 ; 3 3 | = -3

N₂ + 3H₂ ⇌ 2NH₃

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PV = nRT

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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iħ ∂ψ/∂t = Ĥψ

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