Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∫₀^∞ e^(-x²) dx = √π / 2
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
4φ² + 6φ + 2 = 0
det| 7 4 ; 4 8 | = 40
22K
∫₀^∞ e^(-φ²) dφ = √π / 2
∇²ω = 0
∑_{k=1}^{n} k = n(n+1)/2
80K
d/dr [r^2] = 2r^1
ΔS ≥ 0
8β² + 5β + 0 = 0