Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:39Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

6r² + 3r + 1 = 0

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∂y/∂n = 5y

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4φ² + 6φ + 2 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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1n² + 7n + 3 = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 11 5 ; 0 12 | = 132

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d/dt [t^3] = 3t^2

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\oint_C \vec{F}\cdot d\vec{r} = 0

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det| 7 9 ; 1 8 | = 47

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8ψ² + 7ψ + 0 = 0

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