Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:59Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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det| 9 8 ; 3 10 | = 66

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det| 8 9 ; 3 9 | = 45

d/dt [t^3] = 3t^2

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∇ × E = −∂B/∂t

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∇²ω = 0

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6r² + 3r + 1 = 0

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det| 2 3 ; 3 3 | = -3

∇²ω = 0

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det| 9 4 ; 1 10 | = 86

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d/dφ [φ^1] = 1φ^0

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