Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:11Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{r\to 0} \frac{\sin r}{r} = 1

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∇²t = 0

406K

∇²ω = 0

∑_{k=1}^{n} k = n(n+1)/2

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