Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

263K

9r² + 4r + 1 = 0

det| 7 4 ; 4 8 | = 40

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

iħ ∂ψ/∂t = Ĥψ

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∑_{k=1}^{n} k = n(n+1)/2

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11γ² + 3γ + 6 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

439K

∂α/∂ω = 3α

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11z² + 3z + 4 = 0

297K