Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:39Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∂γ/∂θ = 2γ

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∫₀^∞ e^(-t²) dt = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

411K

e^{i\pi} + 1 = 0

PV = nRT

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det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

λ = h/p

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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10t² + 9t + 5 = 0

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