Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

\oint_C \vec{F}\cdot d\vec{r} = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

e^{i\pi} + 1 = 0

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

det| 2 6 ; 0 3 | = 6

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

10ψ² + 5ψ + 0 = 0

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

\lim_{t\to 0} \frac{\sin t}{t} = 1

80K

e^{i\pi} + 1 = 0

359K