Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 03:05Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
186K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
411K
12θ² + 8θ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
det| 7 4 ; 4 8 | = 40
22K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
459K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
80K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 6 ; 1 8 | = 50
359K
E = mc²