Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z

det| 5 4 ; 6 6 | = 6

PV = nRT

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∇²φ = 0

∑_{k=1}^{n} k = n(n+1)/2

186K

11φ² + 4φ + 0 = 0

411K

det| 12 5 ; 4 13 | = 136

det| 9 4 ; 1 10 | = 86

448K

d/dt [t^3] = 3t^2

22K

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

6x² + 6x + 1 = 0

406K

CaCO₃ → CaO + CO₂

E = mc²

ω = 2πf