Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 17:05Z

PV = nRT

8x² + 2x + 7 = 0

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6ω² + 4ω + 4 = 0

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8t² + 4t + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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F = ma

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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2n² + 4n + 0 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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