Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

PV = nRT

411K

4φ² + 6φ + 2 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

6n² + 7n + 6 = 0

459K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

406K

∇²ω = 0

8ψ² + 7ψ + 0 = 0

181K

det| 7 9 ; 1 8 | = 47

80K

d/dr [r^2] = 2r^1