Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:53Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

8θ² + 8θ + 6 = 0

438K

PV = nRT

∇²γ = 0

186K

det| 7 2 ; 7 8 | = 42

411K

det| 1 9 ; 5 2 | = -43

8ψ² + 7ψ + 0 = 0

448K

\lim_{β\to 0} \frac{\sin β}{β} = 1

22K

N₂ + 3H₂ ⇌ 2NH₃

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²β = 0

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

iħ ∂ψ/∂t = Ĥψ

359K