Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:38Z

3γ² + 8γ + 4 = 0

ω = 2πf

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

PV = nRT

det| 11 4 ; 5 12 | = 112

186K

det| 1 4 ; 3 2 | = -10

411K

det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

∇²β = 0

22K

ω = 2πf

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

\lim_{r\to 0} \frac{\sin r}{r} = 1

406K

iħ ∂ψ/∂t = Ĥψ

181K

PV = nRT

80K

det| 5 9 ; 7 6 | = -33

359K

8ψ² + 7ψ + 0 = 0

455K