Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:22Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

det| 1 4 ; 3 2 | = -10

411K

4φ² + 6φ + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

448K

det| 3 1 ; 7 4 | = 5

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

det| 7 4 ; 4 8 | = 40

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0

8β² + 5β + 0 = 0