Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:35Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∂ω/∂β = 7ω

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

det| 5 2 ; 3 6 | = 24

411K

det| 3 3 ; 7 4 | = -9

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

22K

PV = nRT

det| 5 3 ; 7 6 | = 9

459K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

2H₂ + O₂ → 2H₂O

CaCO₃ → CaO + CO₂