Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:17Z
∂ψ/∂φ = 6ψ
11ψ² + 2ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
297K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
252K
λ = h/p
\frac{9}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-t²) dt = √π / 2
299K
\frac{2}{8} \sum_{i=1}^{n} i^{2}
\frac{10}{3} \sum_{i=1}^{n} i^{2}
det| 12 5 ; 1 13 | = 151
d/dt [t^4] = 4t^3
∇ × E = −∂B/∂t