Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

273K

11φ² + 4φ + 0 = 0

263K

e^{i\pi} + 1 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

139K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

108K

2H₂ + O₂ → 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

333K

8ψ² + 7ψ + 0 = 0

160K

det| 4 8 ; 0 5 | = 20

iħ ∂ψ/∂t = Ĥψ

439K

∇²ω = 0

413K

det| 4 7 ; 7 5 | = -29

det| 3 6 ; 0 4 | = 12

297K

N₂ + 3H₂ ⇌ 2NH₃

128K