Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z

11n² + 5n + 4 = 0

E = mc²

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N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

186K

10γ² + 8γ + 7 = 0

411K

4φ² + 6φ + 2 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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CH₄ + 2O₂ → CO₂ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

8ψ² + 7ψ + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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