Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:44Z

CH₄ + 2O₂ → CO₂ + 2H₂O

∇ × E = −∂B/∂t

460K

\oint_C \vec{F}\cdot d\vec{r} = 0

438K

det| 1 1 ; 4 2 | = -2

6t² + 6t + 4 = 0

186K

d/dt [t^3] = 3t^2

411K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

det| 8 4 ; 2 9 | = 64

∑_{k=1}^{n} k = n(n+1)/2

459K

11φ² + 4φ + 0 = 0

406K

4n² + 8n + 6 = 0

10t² + 9t + 5 = 0

181K

\lim_{β\to 0} \frac{\sin β}{β} = 1

80K

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2