Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:37Z

3γ² + 8γ + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

PV = nRT

8ψ² + 7ψ + 0 = 0

186K

PV = nRT

411K

det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

ω = 2πf

\lim_{β\to 0} \frac{\sin β}{β} = 1

459K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

406K

∂n/∂ψ = 6n

∫₀^∞ e^(-ψ²) dψ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃