Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:14Z

e^{i\pi} + 1 = 0

∇ × E = −∂B/∂t

451K

5z² + 8z + 3 = 0

264K

λ = h/p

E = mc²

297K

∂ψ/∂β = 3ψ

252K

det| 6 7 ; 7 7 | = -7

∫₀^∞ e^(-t²) dt = √π / 2

48K

8ψ² + 7ψ + 0 = 0

411K

∇²ψ = 0

d/dt [t^3] = 3t^2

377K

\oint_C \vec{F}\cdot d\vec{r} = 0

299K

∂γ/∂γ = 9γ

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

401K

∑_{k=1}^{n} k = n(n+1)/2

420K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

109K

∫₀^∞ e^(-θ²) dθ = √π / 2

184K