Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z

det| 5 4 ; 6 6 | = 6

∫₀^∞ e^(-θ²) dθ = √π / 2

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∇ × E = −∂B/∂t

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∇²φ = 0

PV = nRT

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E = mc²

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det| 12 5 ; 4 13 | = 136

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

\oint_C \vec{F}\cdot d\vec{r} = 0

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8ψ² + 7ψ + 0 = 0

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det| 3 6 ; 0 4 | = 12

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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