Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-t²) dt = √π / 2

E = mc²

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det| 7 4 ; 4 8 | = 40

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e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

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∇ × E = −∂B/∂t

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λ = h/p

8γ² + 1γ + 1 = 0

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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d/dγ [γ^3] = 3γ^2

∫₀^∞ e^(-θ²) dθ = √π / 2

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F = G m₁m₂ / r²

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det| 10 7 ; 2 11 | = 96