Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 21:51Z

E = mc²

det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

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F = G m₁m₂ / r²

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iħ ∂ψ/∂t = Ĥψ

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 7 4 ; 3 8 | = 44

10ω² + 7ω + 4 = 0

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5φ² + 1φ + 1 = 0

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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