Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
9r² + 4r + 1 = 0
∫₀^∞ e^(-r²) dr = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 2 3 ; 5 3 | = -9
160K
11γ² + 3γ + 6 = 0
det| 4 2 ; 6 5 | = 8
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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∑_{k=1}^{n} k = n(n+1)/2
297K
det| 9 4 ; 1 10 | = 86
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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