Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

λ = h/p

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²β = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

8ψ² + 7ψ + 0 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

∇²r = 0

406K

∇²ω = 0

d/dt [t^3] = 3t^2

181K

2n² + 4n + 0 = 0

80K

d/dr [r^2] = 2r^1

ΔS ≥ 0