Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:37Z

∑_{k=1}^{n} k = n(n+1)/2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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5z² + 8z + 3 = 0

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det| 8 9 ; 3 9 | = 45

∫₀^∞ e^(-ω²) dω = √π / 2

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\lim_{α\to 0} \frac{\sin α}{α} = 1

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

8ψ² + 7ψ + 0 = 0

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iħ ∂ψ/∂t = Ĥψ

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det| 2 3 ; 3 3 | = -3

∫₀^∞ e^(-t²) dt = √π / 2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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1n² + 7n + 3 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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