Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
9r² + 4r + 1 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
439K
∑_{k=1}^{n} k = n(n+1)/2
297K