Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

det| 9 4 ; 1 10 | = 86

460K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

438K

det| 6 4 ; 3 7 | = 30

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

d/dt [t^3] = 3t^2

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

1z² + 3z + 2 = 0

det| 9 5 ; 1 10 | = 85

459K

F = G m₁m₂ / r²

406K

7t² + 3t + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 8 3 ; 4 9 | = 60

10γ² + 8γ + 2 = 0

∇ × E = −∂B/∂t

λ = h/p