Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

E = mc²

460K

\lim_{r\to 0} \frac{\sin r}{r} = 1

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∫₀^∞ e^(-x²) dx = √π / 2

5z² + 8z + 3 = 0

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

7γ² + 8γ + 3 = 0

448K

10γ² + 8γ + 7 = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

F = ma

459K

8ψ² + 7ψ + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

iħ ∂ψ/∂t = Ĥψ

80K

det| 8 9 ; 4 9 | = 36

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