Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 23:43Z

11φ² + 5φ + 5 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

273K

iħ ∂ψ/∂t = Ĥψ

263K

λ = h/p

det| 10 7 ; 3 11 | = 89

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iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

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CH₄ + 2O₂ → CO₂ + 2H₂O

d/dt [t^3] = 3t^2

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det| 2 3 ; 5 3 | = -9

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E = mc²

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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8ψ² + 7ψ + 0 = 0

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E = mc²

12n² + 2n + 2 = 0

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∑_{k=1}^{n} k = n(n+1)/2

2ω² + 5ω + 0 = 0

det| 4 2 ; 0 5 | = 20