Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:12Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∂ω/∂β = 7ω

d/dt [t^3] = 3t^2

186K

∇ × E = −∂B/∂t

411K

det| 3 3 ; 7 4 | = -9

∫₀^∞ e^(-α²) dα = √π / 2

448K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

22K

8ψ² + 7ψ + 0 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K