Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 11 5 ; 0 12 | = 132

186K

det| 1 4 ; 3 2 | = -10

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

d/dx [x^3] = 3x^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

∇²ω = 0